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EASY 26 Jul 2026 View on LeetCode

628. Maximum Product of Three Numbers

</> Solution

class Solution {
    public int maximumProduct(int[] nums) {
        int max1 = Integer.MIN_VALUE;
        int max2 = Integer.MIN_VALUE;
        int max3 = Integer.MIN_VALUE;
        int min1 = Integer.MAX_VALUE;
        int min2 = Integer.MAX_VALUE;
        for (int num : nums) {
            if (num >= max1) {
                max3 = max2;
                max2 = max1;
                max1 = num;
            } else if (num >= max2) {
                max3 = max2;
                max2 = num;
            } else if (num >= max3) {
                max3 = num;
            }
            if (num <= min1) {
                min2 = min1;
                min1 = num;
            } else if (num <= min2) {
                min2 = num;
            }
        }
        return Math.max(max1 * max2 * max3, max1 * min1 * min2);
    }
}

TIME COMPLEXITY

O(n)

SPACE COMPLEXITY

O(1)

TOPICS

Array Greedy Math