1189. Maximum Number of Balloons

class Solution {
    public int maxNumberOfBalloons(String text) {
        int[] freq = new int[26];

        // Count frequency of each character
        for (char ch : text.toCharArray()) {
            freq[ch - 'a']++;
        }

        // "balloon" -> b=1, a=1, l=2, o=2, n=1
        return Math.min(
                Math.min(freq['b' - 'a'], freq['a' - 'a']),
                Math.min(
                        Math.min(freq['l' - 'a'] / 2, freq['o' - 'a'] / 2),
                        freq['n' - 'a']
                )
        );
    }
}

class Solution:
    def maxNumberOfBalloons(self, text: str) -> int:
        freq = [0] * 26

        # Count frequency of each character
        for ch in text:
            freq[ord(ch) - ord('a')] += 1

        # "balloon" -> b=1, a=1, l=2, o=2, n=1
        return min(
            min(freq[ord('b') - ord('a')], freq[ord('a') - ord('a')]),
            min(
                min(freq[ord('l') - ord('a')] // 2,
                    freq[ord('o') - ord('a')] // 2),
                freq[ord('n') - ord('a')]
            )
        )

class Solution {
public:
    int maxNumberOfBalloons(string text) {

        vector<int> freq(26, 0);

        // Count frequency of each character
        for (char ch : text) {
            freq[ch - 'a']++;
        }

        // "balloon" -> b=1, a=1, l=2, o=2, n=1
        return min(
            min(freq['b' - 'a'], freq['a' - 'a']),
            min(
                min(freq['l' - 'a'] / 2,
                    freq['o' - 'a'] / 2),
                freq['n' - 'a']
            )
        );
    }
};

/**
 * @param {string} text
 * @return {number}
 */
var maxNumberOfBalloons = function(text) {

    const freq = new Array(26).fill(0);

    // Count frequency of each character
    for (const ch of text) {
        freq[ch.charCodeAt(0) - 97]++;
    }

    // "balloon" -> b=1, a=1, l=2, o=2, n=1
    return Math.min(
        Math.min(freq['b'.charCodeAt(0) - 97], freq['a'.charCodeAt(0) - 97]),
        Math.min(
            Math.min(
                Math.floor(freq['l'.charCodeAt(0) - 97] / 2),
                Math.floor(freq['o'.charCodeAt(0) - 97] / 2)
            ),
            freq['n'.charCodeAt(0) - 97]
        )
    );
};