3875. Construct Uniform Parity Array I

class Solution {
    public boolean uniformArray(int[] nums1) {
        int oddCount = 0, evenCount = 0;
        for (int x : nums1) {
            if (x % 2 == 0) evenCount++;
            else oddCount++;
        }

        boolean allEven = (oddCount == 0 || oddCount >= 2);
        boolean allOdd = (evenCount == 0 || oddCount >= 1);
        return allEven || allOdd;
    }
}

class Solution:
    def uniformArray(self, nums1):
        oddCount = 0
        evenCount = 0

        for x in nums1:
            if x % 2 == 0:
                evenCount += 1
            else:
                oddCount += 1

        allEven = (oddCount == 0 or oddCount >= 2)
        allOdd = (evenCount == 0 or oddCount >= 1)

        return allEven or allOdd

class Solution {
public:
    bool uniformArray(vector<int>& nums1) {
        int oddCount = 0;
        int evenCount = 0;

        for (int x : nums1) {
            if (x % 2 == 0)
                evenCount++;
            else
                oddCount++;
        }

        bool allEven = (oddCount == 0 || oddCount >= 2);
        bool allOdd = (evenCount == 0 || oddCount >= 1);

        return allEven || allOdd;
    }
};

class Solution {
    uniformArray(nums1) {
        let oddCount = 0;
        let evenCount = 0;

        for (const x of nums1) {
            if (x % 2 === 0)
                evenCount++;
            else
                oddCount++;
        }

        const allEven = (oddCount === 0 || oddCount >= 2);
        const allOdd = (evenCount === 0 || oddCount >= 1);

        return allEven || allOdd;
    }
}