1344. Angle Between Hands of a Clock

/**
 * Problem: LeetCode 1344 - Angle Between Hands of a Clock
 * Difficulty: Medium
 * Language: Java
 * Author: CodeByTushu
 */
class Solution {
    public double angleClock(int hour, int minutes) {
        // Convert 12 to 0 for calculation
        hour %= 12;

        // Hour hand moves 30° per hour + 0.5° per minute
        double hourAngle = hour * 30 + minutes * 0.5;

        // Minute hand moves 6° per minute
        double minuteAngle = minutes * 6;

        // Absolute difference
        double angle = Math.abs(hourAngle - minuteAngle);

        // Return the smaller angle
        return Math.min(angle, 360 - angle);
    }
}

"""
Problem: LeetCode 1344 - Angle Between Hands of a Clock
Difficulty: Medium
Language: Python
Author: CodeByTushu
"""
class Solution:
    def angleClock(self, hour: int, minutes: int) -> float:
        # Convert 12 to 0 for calculation
        hour %= 12

        # Hour hand moves 30° per hour + 0.5° per minute
        hour_angle = hour * 30 + minutes * 0.5

        # Minute hand moves 6° per minute
        minute_angle = minutes * 6

        # Absolute difference
        angle = abs(hour_angle - minute_angle)

        # Return the smaller angle
        return min(angle, 360 - angle)

/**
 * Problem: LeetCode 1344 - Angle Between Hands of a Clock
 * Difficulty: Medium
 * Language: C++
 * Author: CodeByTushu
 */
#include <cmath>
#include <algorithm>

using namespace std;

/**
 * Problem: LeetCode 1344 - Angle Between Hands of a Clock
 * Difficulty: Medium
 * Language: C++
 * Author: CodeByTushu
 */
class Solution {
public:
    double angleClock(int hour, int minutes) {
        // Convert 12 to 0 for calculation
        hour %= 12;

        // Hour hand moves 30° per hour + 0.5° per minute
        double hourAngle = hour * 30.0 + minutes * 0.5;

        // Minute hand moves 6° per minute
        double minuteAngle = minutes * 6.0;

        // Absolute difference
        double angle = abs(hourAngle - minuteAngle);

        // Return the smaller angle
        return min(angle, 360.0 - angle);
    }
};

/**
 * Problem: LeetCode 1344 - Angle Between Hands of a Clock
 * Difficulty: Medium
 * Language: JavaScript
 * Author: CodeByTushu
 */
var angleClock = function(hour, minutes) {
    // Convert 12 to 0 for calculation
    hour %= 12;

    // Hour hand moves 30° per hour + 0.5° per minute
    const hourAngle = hour * 30 + minutes * 0.5;

    // Minute hand moves 6° per minute
    const minuteAngle = minutes * 6;

    // Absolute difference
    const angle = Math.abs(hourAngle - minuteAngle);

    // Return the smaller angle
    return Math.min(angle, 360 - angle);
};